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Author: Admin | 2025-04-28
Concepts:Law of constant proportions, Stoichiometry, Chemical reactionsExplanation:According to the law of constant proportions, a chemical compound always contains its component elements in fixed ratio by mass. In this case, we need to determine the weight of the metal oxide produced when 10g of carbon is heated. We will assume that carbon reacts with oxygen to form carbon dioxide (CO2) as the metal oxide. The molar mass of carbon (C) is approximately 12 g/mol, and the molar mass of oxygen (O) is approximately 16 g/mol. The molar mass of carbon dioxide (CO2) is 12 + 2(16) = 44 g/mol. Therefore, the ratio of the mass of carbon to the mass of carbon dioxide produced is 12g of C produces 44g of CO2. We can set up a proportion to find the mass of CO2 produced from 10g of C.Step by Step Solution:Step 1Calculate the ratio of the mass of carbon to the mass of carbon dioxide: 12g C : 44g CO2.Step 2Set up the proportion for 10g of carbon: (10g C) * (44g CO2 / 12g C) = (10 * 44) / 12.Step 3Calculate the mass of CO2 produced: (10 * 44) / 12 = 36.67g CO2.Final Answer:36.67g of carbon dioxide (CO2) is produced.
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